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First solution in Uncategorized category for Brackets by MKaa01
def checkio(expression):
open_b=[]
ob={'{', '[', '('}
for k in expression:
if k in ob:
open_b.append(k)
if k==')':
if len(open_b)==0 or open_b[-1] != '(':
return False
open_b.pop()
if k==']':
if len(open_b)==0 or open_b[-1] != '[':
return False
open_b.pop()
if k=='}':
if len(open_b)==0 or open_b[-1] != '{':
return False
open_b.pop()
if len(open_b)>0:
return False
return True
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Jan. 18, 2018
