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First solution in Clear category for Brackets by LuigiMoro
import re
pattern_1 = re.compile(".*\{[\w|\+|\-|\*|/|\s]+[\]|\)].*")
pattern_2 = re.compile(".*\[[\w|\+|\-|\*|/|\s]+[\}|\)].*")
pattern_3 = re.compile(".*\([\w|\+|\-|\*|/|\s]+[\}|\]].*")
def checkio(expression):
if (expression.count("{") != expression.count("}") or
expression.count("[") != expression.count("]") or
expression.count("(") != expression.count(")")) :
return False
return (pattern_1.match(expression) or pattern_2.match(expression) or pattern_3.match(expression)) is None
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
July 18, 2014
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