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First solution in Clear category for Brackets by Chramar
def checkio(expression):
brackets=[]
for i in expression:
if i=='(' or i=='[' or i=='{':
brackets.append(i)
if i==')':
if not brackets[-1]=='(' or not brackets:
return False
else:
brackets.pop()
if i==']':
if not brackets or not brackets[-1]=='[':
return False
else:
brackets.pop()
if i=='}':
if not brackets[-1]=='{':
return False
else:
brackets.pop()
if brackets:
return False
return True
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
assert checkio("2+3") == True, "No brackets, no problem"
Oct. 14, 2016
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