Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
Thank you Positronic Lama solution in Uncategorized category for Brackets by Bibiche
pairs = ['()', '{}', '[]', '<>']
# returns whether data contains "good" pair of brackets
def not_pure(data):
return any(p in data for p in pairs)
def checkio(data):
# remove all what is not a bracket
simple = ''.join(s for s in data if s in '([{<)]}>')
# eliminate all "good" pairs of brackets
while not_pure(simple):
for p in pairs:
simple = simple.replace(p, '')
# "good" data if nothing is left after successive eliminations
return len(simple) == 0
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("((5+3)*2+1)") == True, "Simple"
assert checkio("{[(3+1)+2]+}") == True, "Different types"
assert checkio("(3+{1-1)}") == False, ") is alone inside {}"
assert checkio("[1+1]+(2*2)-{3/3}") == True, "Different operators"
assert checkio("(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
May 11, 2013
Comments:
