lambda references creative solution for Boolean Algebra by swagg010164 - python coding challenges

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lambda references solution in Creative category for Boolean Algebra by swagg010164

def boolean(x, y, operation):
    OPERATION_NAMES = {"conjunction": lambda x, y: x & y, \
                        "disjunction": lambda x, y: x | y, \
                        "implication": lambda x, y: (not x) | y, \
                        "exclusive": lambda x, y: (x|y) & (not x & y), \
                        "equivalence": lambda x, y: x == y}
    return OPERATION_NAMES[operation](x, y)

Nov. 20, 2018

Look up in the Dict()

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