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if/elif solution in Clear category for Boolean Algebra by stilus2011
OPERATION_NAMES = ("conjunction", "disjunction", "implication", "exclusive", "equivalence")
def boolean(x, y, operation):
if operation == "conjunction":
return x and y
elif operation == "disjunction":
return x or y
elif operation == "implication":
return y if x else 1
elif operation == "exclusive":
return 1 if x != y else 0
elif operation == "equivalence":
return x == y
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
Jan. 1, 2016
