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do it with lambdas solution in Clear category for Boolean Algebra by piter239
func = {"conjunction": lambda x, y: x and y,
"disjunction": lambda x, y: x or y,
"implication": lambda x, y: not x or y,
"exclusive": lambda x, y: (x or y) and not (x and y),
"equivalence": lambda x, y: not ((x or y) and not (x and y))}
def boolean(x, y, operation):
if operation in func.keys():
return func[operation](x, y)
else:
return True
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
print('All good! Go and check the mission.')
April 20, 2020
