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make a dictionary solution in Clear category for Boolean Algebra by kalauroma7997
boolean = lambda x,y,oper: {"conjunction": x and y, "disjunction": x or y, "implication": not x or y, "exclusive": x != y, "equivalence": x == y}[oper]
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
Nov. 13, 2020
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