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First solution in Clear category for Boolean Algebra by bswitaj
def boolean(x, y, operation):
OPERATION_NAMES = ["conjunction", "disjunction", "implication", "exclusive", "equivalence"]
l=[[0,0,1,0,1],[0,1,0,1,0],[0,1,1,1,0],[1,1,1,0,1]]
if x==0 and y==0:
i=0
if x==1 and y==0:
i=1
if x==0 and y==1:
i=2
if x==1 and y==1:
i=3
# global OPERATION_NAMES
if operation==OPERATION_NAMES[0]:
j=0
if operation==OPERATION_NAMES[1]:
j=1
if operation==OPERATION_NAMES[2]:
j=2
if operation==OPERATION_NAMES[3]:
j=3
if operation==OPERATION_NAMES[4]:
j=4
print(l[i][j])
return int(l[i][j])
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
Oct. 17, 2017
