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1_or_0? solution in Clear category for Boolean Algebra by arkadiusz.nadolski
def boolean(x, y, operation):
if (operation == "conjunction" and (x and y)):
return 1
elif (operation == "disjunction" and (x or y)):
return 1
elif (operation == "implication" and ((not x) or y)):
return 1
elif (operation == "exclusive" and (x ^ y)):
return 1
elif (operation == "equivalence" and not(x ^ y)):
return 1
else:
return 0
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
Jan. 25, 2016
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