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First solution in Uncategorized category for Boolean Algebra by Nuszwkartlo
OPERATION_NAMES = ("conjunction", "disjunction", "implication", "exclusive", "equivalence")
def boolean(x, y, operation):
if (operation == "conjunction"):
if (x == 0 and y == 0):
return False
if (x == 1 and y == 0):
return False
if (x == 0 and y == 1):
return False
if (x == 1 and y == 1):
return True
if (operation == "disjunction"):
if (x == 0 and y == 0):
return False
if (x == 1 and y == 0):
return True
if (x == 0 and y == 1):
return True
if (x == 1 and y == 1):
return True
if (operation == "implication"):
if (x == 0 and y == 0):
return True
if (x == 1 and y == 0):
return False
if (x == 0 and y == 1):
return True
if (x == 1 and y == 1):
return True
if (operation == "exclusive"):
if (x == 0 and y == 0):
return False
if (x == 1 and y == 0):
return True
if (x == 0 and y == 1):
return True
if (x == 1 and y == 1):
return False
if (operation == "equivalence"):
if (x == 0 and y == 0):
return True
if (x == 1 and y == 0):
return False
if (x == 0 and y == 1):
return False
if (x == 1 and y == 1):
return True
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
Nov. 21, 2015
