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Boolean Algebra easy solution solution in Clear category for Boolean Algebra by Kacper_Kapela
def boolean(x, y, operation):
if operation == "conjunction":
if x and y:
return 1
else:
return 0
elif operation == "disjunction":
if x or y:
return 1
else:
return 0
elif operation == "implication":
if x:
return y
else:
return 1
elif operation == "exclusive":
if x==y:
return 0
else:
return 1
elif operation == "equivalence":
if x==y:
return 1
else:
return 0
#W tym zadaniu chodzi o to ze program ma zwrocic wartość 1 lub zależnie od wykonywanej funkcji logicznej
#Program nadaje wartości 0 1 na podstawie ostatniej zmiennej czyli operation :)
#Trzecia zmienna trzeba zrobić w nawiasach!!!
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
Dec. 16, 2015
