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dict & logical solution in Creative category for Boolean Algebra by CDG.Axel
def boolean(x, y, operation):
return {'o': x & y, 'i': x | y, 'm': x ^ 1 | y, 'x': x ^ y, 'q': x ^ y ^ 1}[operation[1:2]]
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert boolean(1, 0, "conjunction") == 0, "and"
assert boolean(1, 0, "disjunction") == 1, "or"
assert boolean(1, 1, "implication") == 1, "material"
assert boolean(0, 1, "exclusive") == 1, "xor"
assert boolean(0, 1, "equivalence") == 0, "same?"
print('All good! Go and check the mission.')
Oct. 12, 2021
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