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First solution in Clear category for Binary Count by HubertDolny
def checkio(number):
x = bin(number)
x= str(x)
howMany=0
for i in range (0, len(x)):
if x[i]=="1":
howMany+=1
return howMany
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(4) == 1
assert checkio(15) == 4
assert checkio(1) == 1
assert checkio(1022) == 9
Oct. 24, 2016