3-liner: find only creative solution for Between Markers by przemyslaw.daniel - python coding challenges

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3-liner: find only solution in Creative category for Between Markers by przemyslaw.daniel

def between_markers(txt, begin, end):
    a, b, c = txt.find(begin), txt.find(end), len(begin)
    return [txt[a+c:b], txt[a+c:], txt[:b], txt][2*(a<0)+(b<0)]

Nov. 18, 2017

Comments:

salaheddineghamri on Jan. 26, 2018, 10:08 p.m.
wow

facebreeze on March 15, 2018, 2:40 p.m.
This solution is hard to understand!

przemyslaw.daniel on March 15, 2018, 7:45 p.m.
That was the purpose for creative category.

PHANTOM0308 on April 23, 2018, 4:37 p.m.
It is such a concise solution! However, I'm quite confused about the function of [] in the last step after return. is [] a shortcut for if statement? or something else?

przemyslaw.daniel on April 23, 2018, 7:12 p.m.
You can write it following way to understand it better <pre class='brush: python'>v = [txt[a+c:b], txt[a+c:], txt[:b], txt] return v[2*(a<0)+(b<0)] </pre>

kiplimock on May 22, 2020, 8:43 a.m.
Hi, could you explain to me how the return statement does the slicing? I'd like to understand

Layort on Nov. 27, 2021, 8:30 a.m.
That's to say: a < 0 and b < 0 is bool type, if a < 0 is true then we get 0 or we get 1. With this ,we can choose different type of slicing in list v

alekseykonotop on Sept. 15, 2018, 7:29 p.m.
WOW! Cool!

kiplimock on May 22, 2020, 8:42 a.m.
Hey! So brief and it works! Could you (or anyone else here) explain to me your return statement slices the text! I've struggled to try and grasp it.

Henry_Du on Oct. 21, 2021, 8:45 a.m.
True = 1, False =0 <ul> <li>(a<0:True & b<0:True)==>[2(a<0)+(b<0)]=3 * (a<0:True & b<0:False)==>[2(a<0)+(b<0)]=2 * (a<0:False & b<0:True)==>[2(a<0)+(b<0)]=1 * (a<0:False & b<0:False)==>[2(a<0)+(b<0)]=0</li> </ul> Therefore, you can figure out the position of the list [txt[a+c:b], txt[a+c:], txt[:b], txt]. Very smart! Salute!

rvdek on May 28, 2021, 11:42 a.m.
Very smart !

Mylinear on April 15, 2022, 2:44 a.m.
I scrutinized your solution at <a href="https://pythontutor.com/">https://pythontutor.com/</a> step by step to understand and after some time I'm amazed at your solution. I take my hat off to the solution.

przemyslaw.daniel on April 15, 2022, 11:49 a.m.
pythontutor.com seems to be very nice website for learners

Strings Theory

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