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sub and lambda solution in Clear category for Backward Each Word by seriousCnam
import re
def backward_string_by_word(text: str) -> str:
return(re.sub(r"([\w]*)", lambda x: x.group(0)[::-1], text))
if __name__ == '__main__':
print("Example:")
print(backward_string_by_word(''))
# These "asserts" are used for self-checking and not for an auto-testing
assert backward_string_by_word('') == ''
assert backward_string_by_word('world') == 'dlrow'
assert backward_string_by_word('hello world') == 'olleh dlrow'
assert backward_string_by_word('hello world') == 'olleh dlrow'
assert backward_string_by_word('welcome to a game') == 'emoclew ot a emag'
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May 4, 2020
