1-liner clear solution for Backward Each Word by Stensen - python coding challenges

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1-liner solution in Clear category for Backward Each Word by Stensen

backward_string_by_word = lambda t: " ".join([i[::-1] for i in t.split(" ")])

Sept. 21, 2020

Comments:

samarism on Sept. 25, 2020, 2:39 a.m.
why do we need to create a lambda?

Stensen on Sept. 25, 2020, 1:18 p.m.
Well, lambda is an anonymous function replaces the ordinary syntax of the function. So instead of using the ordinary syntax: <pre class='brush: python'>def backward_string_by_word(text): backwarded_words = [word[::-1] for word in text.split()] return " ".join(backwarded_words) </pre> We could make it handy as "pythonic" variable which we have the tendency to call it an anonymous function Just like my Solution. Please Consider Voting On My Solution :)

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