del a[-1:] clear solution for Backspace Apply by StefanPochmann - python coding challenges

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del a[-1:] solution in Clear category for Backspace Apply by StefanPochmann

def backspace_apply(s: str) -> str:
    a = []
    for c in s:
        if c == '#':
            del a[-1:]
        else:
            a.append(c)
    return ''.join(a)

Feb. 4, 2022

Comments:

StefanPochmann on Feb. 4, 2022, 6:22 p.m.
Checked all solutions, didn't see anybody doing this. Even though quite a few people used the inefficient `a = a[:-1]`. Weird.

veky on Feb. 5, 2022, 5:52 p.m.
You could have titled your solution `delslice` (for quite a long time it was a separate method, and apparently still people think of it as a separate API from `delitem`:).

StefanPochmann on Feb. 5, 2022, 9:42 p.m.
Do they? How many people ever think about either of those? I didn't :-)

veky on Feb. 6, 2022, 12:08 a.m.
Obviously not under these names, but I just meant to say that `del`ing a slice is in the separate bucket from `del`ing an item itself, though the syntax is basically the same. (Similarly how many people can use `yield` fine, yet it would never occur to them to use `yield from` where appropriate.:)

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