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First: inclunding the rounding to 8 digits solution in Clear category for Achilles and the Tortoise by Red_Ale
def chase(a1_speed, t2_speed, advantage):
return round((advantage + ((t2_speed * advantage)/(a1_speed - t2_speed))), 8)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
def almost_equal(checked, correct, significant_digits):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert almost_equal(chase(6, 3, 2), 4, 8), "example"
assert almost_equal(chase(10, 1, 10), 11.111111111, 8), "long number"
July 4, 2022
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