First uncategorized solution for Achilles and the Tortoise by Bronepoezd - python coding challenges

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First solution in Uncategorized category for Achilles and the Tortoise by Bronepoezd

def chase(a1_speed, t2_speed, advantage):
    return a1_speed * advantage / ( a1_speed - t2_speed )

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    def almost_equal(checked, correct, significant_digits):
        precision = 0.1 ** significant_digits
        return correct - precision < checked < correct + precision

    assert almost_equal(chase(6, 3, 2), 4, 8), "example"
    assert almost_equal(chase(10, 1, 10), 11.111111111, 8), "long number"

Sept. 2, 2015

Comments:

Blastus on July 27, 2016, 3:30 p.m.
<p>Great job on solving the paradox! Your function is short, does not have any apparent problems, and is fairly simple to understand. You only need some documentation and to check for PEP8 violations: <a href="http://pep8online.com/s/nImakulH">http://pep8online.com/s/nImakulH</a></p>

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