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六つ solution in Clear category for Acceptable Password VI by veky
def is_acceptable_password(p: str) -> bool:
return ('password' not in p.casefold()
and (len(p) >= 10
or len(p) >= 6
and any(c.isdigit() for c in p)
and not p.isdigit())
and len(set(p)) >= 3)
March 19, 2020
