First uncategorized solution for Acceptable Password VI by melitaele - python coding challenges

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First solution in Uncategorized category for Acceptable Password VI by melitaele

def is_acceptable_password(a):
    a = a.replace(' ', '')
    if len(a) <= 6:
        return False
    elif (a.isdigit() or a.isalpha()) and len(a) <= 9:
        return False
    elif 'password' in a.lower():
        return False
    return len(set(a)) >= 3

April 23, 2021

Comments:

melitaele on April 23, 2021, 3:59 p.m.
<p>Quite a few ifs here now, but at least all the code is not one long long string.</p>

melitaele on April 23, 2021, 4:11 p.m.
<p>Quite a few ifs here now, but at least all the code is not one long long line.</p>

Strings Theory

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