Evoluotion, the final completion (part VI). clear solution for Acceptable Password VI by Tinus_Trotyl - python coding challenges

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Evoluotion, the final completion (part VI). solution in Clear category for Acceptable Password VI by Tinus_Trotyl

# Taken from mission Acceptable Password V

# Taken from mission Acceptable Password IV

# Taken from mission Acceptable Password III

# Taken from mission Acceptable Password II

# Taken from mission Acceptable Password I

def is_acceptable_passwordI(password: str) -> bool:
    return len(password) > 6

def is_acceptable_passwordII(password):
    return is_acceptable_passwordI(password) and any([c in '0123456789' for c in password])

def is_acceptable_passwordIII(password):
    return is_acceptable_passwordII(password) and not all([c in '0123456789' for c in password])

def is_acceptable_passwordIV(password):
    return is_acceptable_passwordIII(password) or len(password) > 9

def is_acceptable_passwordV(password):
    return is_acceptable_passwordIV(password) and not 'password' in password.lower()

def is_acceptable_password(password):
    return is_acceptable_passwordV(password) and len(set(list(password))) >= 3

Oct. 13, 2020

Comments:

Andrz on March 29, 2021, 9:40 a.m.
Interesting desicion. You can do it simplier. You can use c.isdigit() instead of c in '0123456789'. And you don't need cast password to list. Set can use it as is: set(password).

Strings Theory

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