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First solution in Clear category for Acceptable Password V by robertabegg
# Taken from mission Acceptable Password IV
def is_acceptable_password(password: str) -> bool:
return (6 < len(password) > sum([c.isdigit() for c in password]) > 0
or len(password) > 9) \
and password.upper().find("PASSWORD") == -1
if __name__ == "__main__":
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password("short") == False
assert is_acceptable_password("short54") == True
assert is_acceptable_password("muchlonger") == True
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
assert is_acceptable_password("1234567") == False
assert is_acceptable_password("12345678910") == True
assert is_acceptable_password("password12345") == False
assert is_acceptable_password("PASSWORD12345") == False
assert is_acceptable_password("pass1234word") == True
print("Coding complete? Click 'Check' to earn cool rewards!")
Aug. 29, 2021
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