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First solution in Clear category for Acceptable Password V by paolo.carlevero
def is_acceptable_password(psw):
if 'password' not in psw.lower():
if len(psw) > 6 and any(c.isdigit() for c in psw) and any(c.isalpha() for c in psw) or len(psw) > 9:
return True
return False
April 19, 2021
