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First solution in Clear category for Acceptable Password V by lisovsky
# Taken from mission Acceptable Password IV
def is_acceptable_password(password: str) -> bool:
if len(password) <= 6:
return False
if "password" in password.lower():
return False
n = sum([c.isdigit() for c in password])
if (len(password) == n or n == 0) and len(password) <= 9:
return False
return True
if __name__ == "__main__":
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password("short") == False
assert is_acceptable_password("short54") == True
assert is_acceptable_password("muchlonger") == True
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
assert is_acceptable_password("1234567") == False
assert is_acceptable_password("12345678910") == True
assert is_acceptable_password("password12345") == False
assert is_acceptable_password("PASSWORD12345") == False
assert is_acceptable_password("pass1234word") == True
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Sept. 15, 2022
