Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Creative category for Acceptable Password V by ladeischicov
# Taken from mission Acceptable Password IV
# Taken from mission Acceptable Password III
# Taken from mission Acceptable Password II
# Taken from mission Acceptable Password I
def is_acceptable_password(password: str) -> bool:
if len(password) > 9 and 'password' not in password.lower():
return True
if 6 < len(password) < 9 and any(ch.isdigit() for ch in password) and any(i.isalpha() for i in password) and 'password' not in password.lower():
return True
else:
return False
print("Example:")
print(is_acceptable_password("short"))
# These "asserts" are used for self-checking
assert is_acceptable_password("short") == False
assert is_acceptable_password("short54") == True
assert is_acceptable_password("muchlonger") == True
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
assert is_acceptable_password("1234567") == False
assert is_acceptable_password("12345678910") == True
assert is_acceptable_password("password12345") == False
assert is_acceptable_password("PASSWORD12345") == False
assert is_acceptable_password("pass1234word") == True
print("The mission is done! Click 'Check Solution' to earn rewards!")
Feb. 17, 2023
Comments:
