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First solution in Clear category for Acceptable Password V by kirill.cuc
def is_acceptable_password(password: str) -> bool:
с1 = len(password) > 6
с2 = any(map(str.isdigit, password)) and not password.isdigit()
с3 = len(password) > 9
с4 = 'password' not in password.lower()
return с1 and (с2 or с3) and с4
if __name__ == "__main__":
print("Example")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password("short") == False
assert is_acceptable_password("short54") == True
assert is_acceptable_password("muchlonger") == True
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
assert is_acceptable_password("1234567") == False
assert is_acceptable_password("12345678910") == True
assert is_acceptable_password("password12345") == False
assert is_acceptable_password("PASSWORD12345") == False
assert is_acceptable_password("pass1234word") == True
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May 13, 2022
