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Acceptable Password V solution in Clear category for Acceptable Password V by faccanoni
def is_acceptable_password(password: str) -> bool:
if "password" in password.lower():
return False
Dig=sum([c.isdigit() for c in password])
return (len(password)>6 and Dig!=0 and Dig!=len(password)) or (len(password)>9)
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('short54') == True
assert is_acceptable_password('muchlonger') == True
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
assert is_acceptable_password('12345678910') == True
assert is_acceptable_password('password12345') == False
assert is_acceptable_password('PASSWORD12345') == False
assert is_acceptable_password('pass1234word') == True
print("Coding complete? Click 'Check' to earn cool rewards!")
Jan. 24, 2021
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