Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
readable pass 5 solution in Clear category for Acceptable Password V by entreoutros
def is_acceptable_password(password: str) -> bool:
le = len(password)
b = [char.isdigit() for char in password]
return (le > 6 and b != b[:1]*len(b) or le > 9) and not 'password' in password.lower()
if __name__ == "__main__":
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password("short") == False
assert is_acceptable_password("short54") == True
assert is_acceptable_password("muchlonger") == True
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
assert is_acceptable_password("1234567") == False
assert is_acceptable_password("12345678910") == True
assert is_acceptable_password("password12345") == False
assert is_acceptable_password("PASSWORD12345") == False
assert is_acceptable_password("pass1234word") == True
print("Coding complete? Click 'Check' to earn cool rewards!")
Sept. 25, 2021
Comments:
