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First solution in Clear category for Acceptable Password V by dannystaple
# Taken from mission Acceptable Password IV
def is_acceptable_password(password: str) -> bool:
# your code here
long_enough = len(password) > 6
long_enough_anyway = len(password) > 9
if "password" in password.lower():
return False
if long_enough_anyway:
return True
has_digits = any(c.isdigit() for c in password)
all_digits = password.isdigit()
return long_enough and has_digits and not all_digits
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('short54') == True
assert is_acceptable_password('muchlonger') == True
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
assert is_acceptable_password('12345678910') == True
assert is_acceptable_password('password12345') == False
assert is_acceptable_password('PASSWORD12345') == False
assert is_acceptable_password('pass1234word') == True
print("Coding complete? Click 'Check' to earn cool rewards!")
Aug. 10, 2020
