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First solution in Clear category for Acceptable Password V by carel.anthonissen
import re
def is_acceptable_password(password: str) -> bool:
return password.lower().find('password') == -1 and \
(
(len(password)>6 and \
re.search(r'\d',password) is not None and \
re.search(r'\D',password) is not None \
) or \
len(password)>9
)
May 7, 2020
