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with comment solution in Clear category for Acceptable Password V by Sim0000
def is_acceptable_password(password: str) -> bool:
# C1 : the length should be bigger than 6;
# C2 : should contain at least one digit, but cannot consist of just digits.
# C3 : having numbers or containing just numbers does not apply to the password longer than 9.
# C4 : a string should not contain the word "password" in any case.
c1 = len(password) > 6
c2 = any(map(str.isdigit, password)) and not password.isdigit()
c3 = len(password) > 9
c4 = 'password' not in password.lower()
return c1 and (c2 or c3) and c4
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('short54') == True
assert is_acceptable_password('muchlonger') == True
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
assert is_acceptable_password('12345678910') == True
assert is_acceptable_password('password12345') == False
assert is_acceptable_password('PASSWORD12345') == False
assert is_acceptable_password('pass1234word') == True
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April 1, 2020
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