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First solution in Clear category for Acceptable Password V by Mycroft0121
# Taken from mission Acceptable Password IV
# Taken from mission Acceptable Password III
# Taken from mission Acceptable Password II
# Taken from mission Acceptable Password I
def is_acceptable_password(password: str) -> bool:
# your code here
l =len(password)
return ("password" not in password.lower()) and ((l>6 and any(char.isdigit() for char in password) and not all(char.isdigit() for char in password)) or l>9)
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('short54') == True
assert is_acceptable_password('muchlonger') == True
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
assert is_acceptable_password('12345678910') == True
print("Coding complete? Click 'Check' to earn cool rewards!")
June 12, 2021
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