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Second solution in Clear category for Acceptable Password V by MBM_1607
def is_acceptable_password(password: str) -> bool:
return (
(
len(password) > 6
and any(map(str.isdigit, password))
and not all(map(str.isdigit, password))
or len(password) >= 10
)
and not "password" in password.lower()
)
April 5, 2020
