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add more stuff solution in Creative category for Acceptable Password V by Luke747
def is_acceptable_password(password):
cd = 0
cnd = 0
if 'password' in password.lower():
return False
for i in password:
if i.isdigit():
cd += 1
else:
cnd += 1
if cd > 0 and cnd > 0:
break
if len(password) < 9:
return True if len(password) > 6 and cd > 0 and cnd > 0 else False
else:
return True
return None
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('short54') == True
assert is_acceptable_password('muchlonger') == True
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
assert is_acceptable_password('12345678910') == True
assert is_acceptable_password('password12345') == False
assert is_acceptable_password('PASSWORD12345') == False
assert is_acceptable_password('pass1234word') == True
print("Coding complete? Click 'Check' to earn cool rewards!")
July 21, 2021
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