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Nice solution in Speedy category for Acceptable Password V by Detka_v_Ogne
def is_acceptable_password(password: str) -> bool:
L = len(password)
a1 = L > 6
a2 = not password.isdigit() if L < 10 else True
a3 = any(x for x in password if x.isdigit()) if L < 10 else True
a4 = False if ('password' in password.lower()) else True
return all([a1, a2, a3, a4])
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('short54') == True
assert is_acceptable_password('muchlonger') == True
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
assert is_acceptable_password('12345678910') == True
assert is_acceptable_password('password12345') == False
assert is_acceptable_password('PASSWORD12345') == False
assert is_acceptable_password('pass1234word') == True
print("Coding complete? Click 'Check' to earn cool rewards!")
June 12, 2020
