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Acceptable Password V one liner solution in Uncategorized category for Acceptable Password V by Aleksandra_Niewiadomska
# Taken from mission Acceptable Password IV
# Taken from mission Acceptable Password III
def is_acceptable_password(password: str) -> bool:
return len(password) > 6 and "password" not in password.lower() and (len(password) > 9 or (any(str.isdigit() for str in password) and not password.isdigit()))
print("Example:")
print(is_acceptable_password("short"))
# These "asserts" are used for self-checking
assert is_acceptable_password("short") == False
assert is_acceptable_password("short54") == True
assert is_acceptable_password("muchlonger") == True
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
assert is_acceptable_password("1234567") == False
assert is_acceptable_password("12345678910") == True
assert is_acceptable_password("password12345") == False
assert is_acceptable_password("PASSWORD12345") == False
assert is_acceptable_password("pass1234word") == True
print("The mission is done! Click 'Check Solution' to earn rewards!")
Feb. 1, 2023