Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Acceptable Password IV by wbl4126
def is_acceptable_password(password: str) -> bool:
return (
len(password) > 6
and any(map(str.isdigit, password))
and not all(map(str.isdigit, password))
) or len(password) > 9
April 1, 2020
