First clear solution for Acceptable Password IV by tokareva.anastasiya.tch - python coding challenges

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First solution in Clear category for Acceptable Password IV by tokareva.anastasiya.tch

import re 
def is_acceptable_password(password):
    return bool(re.match(r'(?=.*\d)(?=.*\D)(.+){6,}|(.+){9,}', password))

Sept. 17, 2022

Comments:

Kolia951 on Nov. 11, 2022, 10:11 a.m.
Very smart idea using regular expression here! Would you please explain what does that mean (?=.*\d) ?

jakubbortlik on Nov. 30, 2022, 3:25 p.m.
Search for `(?=...)` in the <a href="https://docs.python.org/3.12/library/re.html">docs</a>. It's a lookahead assertion: <blockquote> Matches if ... matches next, but doesn’t consume any of the string. This is called a lookahead assertion. For example, Isaac (?=Asimov) will match 'Isaac ' only if it’s followed by 'Asimov'. </blockquote> The pattern can be simplified in the original `(.+){6,}` tests if there are "six or more repetitions" of "one or more characters", but it can be just "six or more repetitions of one character (same for 9 characters): `re.match(r'(?=.\d)(?=.\D).{6,}|.{9,}', password)`.

Kolia951 on Dec. 1, 2022, 7:49 p.m.
Thank you for the explanation. This is really not simple topic to understand.

Strings Theory

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