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Double len, any and sum generator solution in Clear category for Acceptable Password IV by r_tchaik
def is_acceptable_password(password: str) -> bool:
return any((len(password) > 9, 0 < sum(ch.isdigit() for ch in password) < len(password) > 6))
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('short54') == True
assert is_acceptable_password('muchlonger') == True
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
assert is_acceptable_password('12345678910') == True
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July 30, 2020
