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Decisions... solution in Clear category for Acceptable Password IV by lucas.stonedrake
# Taken from mission Acceptable Password III
# Taken from mission Acceptable Password I
import re
def is_acceptable_password(password: str) -> bool:
if 6 < len(password) < 9 and re.search('[0-9]', password) and not password.isdigit(): return True
elif len(password) > 9: return True
else: return False
Nov. 8, 2020