Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Acceptable Password III by snowd2020
# Taken from mission Acceptable Password II
import re
def is_acceptable_password(password: str) -> bool:
if(len(re.findall('\d+',password))!=0) and (len(re.findall('\D+',password))!=0) and (len(re.findall('\S{7}',password))!=0):
return True
else:
return False
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('muchlonger') == False
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
print("Coding complete? Click 'Check' to earn cool rewards!")
Dec. 9, 2020
