really nice clear solution for Acceptable Password III by rafal.pawlowski - python coding challenges

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really nice solution in Clear category for Acceptable Password III by rafal.pawlowski

is_acceptable_password = lambda p: 0 < sum(c.isdigit() for c in p) < len(p) > 6

March 18, 2020

Comments:

Patrick_Devaney on April 2, 2020, 3:24 p.m.
Didn't know you could do that!

dusty5213 on April 7, 2020, 8:09 a.m.
Sorry but absolutely no idea what's going on here ;-?

lifeshow30s on July 9, 2020, 9:25 a.m.
go through all the best solutions, you could find lambda everywhere

Jonethan on Sept. 24, 2020, 12:11 p.m.
You can use str.isdecimal() instead of str.isdigit()

Thanongsak on Jan. 10, 2021, 9:32 a.m.
very short

mikaeldovbnia on April 30, 2022, 2:50 p.m.
Nice understandable solution.

2502019108 on Oct. 19, 2022, 10:56 a.m.
OMG!

sarahsorlien on Jan. 4, 2023, 8:24 p.m.
clever

warunlock on May 1, 2023, 5:33 p.m.
very good

Zuosy on July 6, 2024, 1:24 a.m.
NB

mu_py on Oct. 28, 2024, 9:13 p.m.
Thanks for pointing out that even those chains of comparisions are possible in Python.

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