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First solution in Clear category for Acceptable Password III by mazeua
# Taken from mission Acceptable Password II
def is_acceptable_password(password: str) -> bool:
return len(password)>6 and any([x.isdigit() for x in password]) and not all([x.isdigit() for x in password])
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('muchlonger') == False
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
print("Coding complete? Click 'Check' to earn cool rewards!")
Sept. 18, 2020
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