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0 < isdigit < len(password) solution in Clear category for Acceptable Password III by kcab98
def is_acceptable_password(password: str) -> bool:
return len(password) > 6 and 0 < sum(chr.isdigit() for chr in password) < len(password)
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('muchlonger') == False
assert is_acceptable_password('ashort') == False
assert is_acceptable_password('muchlonger5') == True
assert is_acceptable_password('sh5') == False
assert is_acceptable_password('1234567') == False
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Dec. 10, 2020