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First solution in Clear category for Acceptable Password III by brainexploded
# Taken from mission Acceptable Password II
# Taken from mission Acceptable Password I
def is_acceptable_password(password: str) -> bool:
digit_flag = False
nondigit_flag = False
for i in password:
if i.isdigit():
digit_flag = True
else:
nondigit_flag = True
if digit_flag and nondigit_flag:
break
return len(password) > 6 and digit_flag and nondigit_flag
print("Example:")
print(is_acceptable_password("short"))
# These "asserts" are used for self-checking
assert is_acceptable_password("short") == False
assert is_acceptable_password("muchlonger") == False
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
assert is_acceptable_password("1234567") == False
print("The mission is done! Click 'Check Solution' to earn rewards!")
Aug. 8, 2023
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