Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Acceptable Password III by StanislauL
def is_acceptable_password(password: str) -> bool:
return (len(password)>6 and
any([x.isdigit() for x in password]) and
any([x.isalpha() for x in password]))
Aug. 24, 2020
Comments: