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1 Line solution in Speedy category for Acceptable Password III by Alex_4444D
def is_acceptable_password(password: str) -> bool:
return len(password) > 6 and any(char.isdigit() for char in password) and not password.isdigit()
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password("short") == False
assert is_acceptable_password("muchlonger") == False
assert is_acceptable_password("ashort") == False
assert is_acceptable_password("muchlonger5") == True
assert is_acceptable_password("sh5") == False
assert is_acceptable_password("1234567") == False
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Nov. 7, 2021
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