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First solution in Clear category for Acceptable Password II by shaggyrobot
def is_acceptable_password(password):
return len(password) > 6 and any(x.isdigit() for x in password)
if __name__ == '__main__':
print("Example:")
print(is_acceptable_password('short'))
# These "asserts" are used for self-checking and not for an auto-testing
assert is_acceptable_password('short') == False
assert is_acceptable_password('muchlonger') == False
assert is_acceptable_password('ashort') == False
print("Coding complete? Click 'Check' to earn cool rewards!")
Sept. 16, 2020
